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5x^2+30x+17=0
a = 5; b = 30; c = +17;
Δ = b2-4ac
Δ = 302-4·5·17
Δ = 560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{560}=\sqrt{16*35}=\sqrt{16}*\sqrt{35}=4\sqrt{35}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-4\sqrt{35}}{2*5}=\frac{-30-4\sqrt{35}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+4\sqrt{35}}{2*5}=\frac{-30+4\sqrt{35}}{10} $
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